Posted by **gift onos** on Sunday, September 23, 2012 at 10:38pm.

A box contain 12 cell phones of which 4 are defective.all phones look alike.3 phones are drawn randomly what is the probability.1 all the 3 bulbs are defective.2 at least 2 of the bulbs chosen are defective.3 at most 2 of the bulbs chosen are defective.hint use combination analysis

- math -
**Reiny**, Sunday, September 23, 2012 at 11:12pm
prob(defective) = 4/12 = 1/3

prob(not defective) = 2/3

1. all 3 defective ---- prob = (1/3)^3 = 1/27

2. at least 2 defective

----> 2 defective or 3 defective

prob = C(3,2)(1/3)^2 (2/3) + (1/3)^3

= 3(2/27) + 1/27 = 7/27

3. at most 2 ---> 0 defective, 1 defect, or 2 defective

or exclude all 3 defectiv

= 1 - 1/27 = 26/27

BTW,

Where do the bulbs enter the picture when talking about cell phones

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