Posted by **mary** on Sunday, September 23, 2012 at 10:14pm.

Calculate the pH and pOH of a 0.00002M solution of acetic acid.

- analytical chemisty -
**DrBob222**, Sunday, September 23, 2012 at 10:24pm
Call acetic acid HAc.

............HAc ==> H^+ + Ac^-

initial..2E-5M......0.......0

change....-x........x........x

equil...2E-5-x......x........x

Ka = (H^+)(Ac^-)/(HAc)

Substitute and solve for H^+, then

pH = -log(H^+).

Then pH + pOH = pKw = 14

Youknow pH and pKw, solve for pOH.

Note: I think you must solve the quadratic; i.e., you will not be able to make simplifying assumptions.

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