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September 14, 2014

September 14, 2014

Posted by **Amanda and Travis** on Sunday, September 23, 2012 at 9:19pm.

- Physics -
**Steve**, Monday, September 24, 2012 at 10:50amrange is v^2 sin(2θ)/g

height is v^2 sin^2(θ)/2g

so,

sin(2θ) = sin^2(θ)/2

2sinθcosθ = sin^2(θ)/2

4cosθ = sinθ

16cos^2(θ) = sin^2(θ) = 1 - cos^2(θ)

17cos^2(θ) = 1

cosθ = 1/√17

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