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Posted by **Soph** on Sunday, September 23, 2012 at 7:06pm.

Vi= initial velocity

vf=final velocity

a= acceleration

d=distance

t=time

I found out that it takes Jack 3 seconds to reach where the bus was originally at the 12m. But after that i have no clue how to finish it.

- Physics? clueless on what to do -
**Damon**, Sunday, September 23, 2012 at 8:00pmbus goes distance d

Jack goes distance (d+12)

d = (1/2) a t^2 = .4 t^2

d+12 = 4 t so d = 4 t - 12

4 t - 12 = .4 t^2

.4 t^2 - 4 t + 12 = 0

t = [ 4 +/- sqrt (16 -.16*12) / .8

t = [ 4 +/- 3.75 ] /.8

t = 9.69 or .313

the .313 solution is impossible because he has not run 12 meters by then

so he catches the bus after 9.69 seconds.

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