Posted by **etulan** on Saturday, September 22, 2012 at 4:39pm.

a man walks 8km north and 5km in a direction east of north.find the distance from the starting point

- math -
**Steve**, Saturday, September 22, 2012 at 4:56pm
8kmN moves (0,8)

5km NE moves (3.5,3.5)

add them up to get (3.5,11.5)

distance is thus √(3.5^2 + 11.5^2) = 12.0

- math -
**Anonymous**, Saturday, September 22, 2012 at 4:57pm
This is a pythagorean theorem problem:

a^2 + b^2 = c^2

You have two sides and you are going to solve for c.

- math -
**Anonymous**, Wednesday, February 17, 2016 at 3:39pm
11

- physics -
**Ben**, Monday, October 17, 2016 at 4:01pm
1. A man walks 10km east and 20km south the displacement of the man from initial position

2. In figure below R= 30, find x and Y respectively.

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