Find the intercepts of the graph of the equation
y= x^2 -4
________
X^2 -9
a. there is no intercept
b. the intercept(s) is/are
type the ordered pair, using intergers or fractions
y = p(x)/q(x), a fraction. As with all fractions, it is zero when the numerator is zero. So, there are x-intercepts where x^2-4 = 0 (as long as x^2-9 is not also zero)
there is a y-intercept where x=0
that help?
yes that does some. I am having to take this for nursing even when we do not use it. I am having a hard time with this course. Thanks alot!!
To find the intercepts of the graph of the equation, we need to determine the values of x where the graph intersects the x-axis and y-axis.
To find the x-intercepts, we set y = 0 and solve for x.
0 = x^2 - 4
x^2 = 4
Taking the square root of both sides, we get:
x = ±2
So, the x-intercepts are (-2, 0) and (2, 0).
To find the y-intercepts, we set x = 0 and solve for y.
y = 0^2 - 4
y = -4
So, the y-intercept is (0, -4).
Therefore, the intercepts of the graph of the equation y = (x^2 - 4) / (x^2 - 9) are:
- x-intercepts: (-2, 0) and (2, 0)
- y-intercept: (0, -4)
The correct answer is b. The intercept(s) is/are:
(-2, 0), (2, 0), (0, -4)