Posted by ladybug on Saturday, September 22, 2012 at 4:13pm.
what can you figure out? Consider zeros, asymptotes of all kinds, maxima and minima.
So, there is not one in particular that this question falls under then. Thats where I have my problem is not knowing what and where to start from as far as the formulas for each equation goes. I did good with algebra but come to this my brain has just stopped. Like I said ealier I know I do not need this class for nursing but still.
since the numerator is 13x+13, r(x) = 0 when x = -1
since the denominator is 5x+15, the denominator is zero when x = -3, so there is a vertical asymptote at x = -3.
As x gets huge, r(x) =~ 13x/5x = 13/5, so there is a horizontal asymptote at y = 13/5
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