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December 20, 2014

December 20, 2014

Posted by **ladybug** on Saturday, September 22, 2012 at 4:13pm.

r(x)= 13x + 13

________

5x + 15

- pre-calculus -
**Steve**, Saturday, September 22, 2012 at 4:49pmwhat can you figure out? Consider zeros, asymptotes of all kinds, maxima and minima.

- pre-calculus -
**ladybug**, Saturday, September 22, 2012 at 5:16pmSo, there is not one in particular that this question falls under then. Thats where I have my problem is not knowing what and where to start from as far as the formulas for each equation goes. I did good with algebra but come to this my brain has just stopped. Like I said ealier I know I do not need this class for nursing but still.

- pre-calculus -
**Steve**, Sunday, September 23, 2012 at 7:12amsince the numerator is 13x+13, r(x) = 0 when x = -1

since the denominator is 5x+15, the denominator is zero when x = -3, so there is a vertical asymptote at x = -3.

As x gets huge, r(x) =~ 13x/5x = 13/5, so there is a horizontal asymptote at y = 13/5

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