Posted by Danielle on Saturday, September 22, 2012 at 2:55pm.
what are the zeros for 1x^5+2x^4+4x^3+19x^2+9x^2+9x-5?
Math - Steve, Saturday, September 22, 2012 at 4:33pm
5th-degree polynomials are not open to solution in general, so look for low-hanging fruit using synthetic division.
any rational roots must be ±1 or ±5.
no joy there.
not sure how to find the roots analytically. You may have to use some iterative methods. Don't know whether you have studied those yet.
If you go to wolframalpha.com and enter
solve x^5+2x^4+4x^3+19x^2+9x^2+9x-5 = 0
you will get the roots, but not much help in figuring out the exact values using radicals.
Answer This Question
More Related Questions
- Rational Zeros - List all possible rational zeros for the polynomial below. Find...
- Math(pre-calc) - what are all the real zeros for 1x^5+2x^4+4x^3+19x^2+9x-5?
- MATH ALGEBRA - f(x)=6x^3+19x^2+8x-5 find all the zeros of the given function
- algebra - List all possible rational zeros for the polynomial below. Find all ...
- Math - Possible or Potential rational zeros - List all possible (or potential) ...
- find the zeros of the function - f(x)= 4x^2 + 19x - 5
- Algebra - Find the product (1 - 3x) (x^2 - 6x - 4)x^2 A. -3x^5 + 19x^4 + 6x^3 - ...
- pre-calc - what are all the real zeros for 1x^5+2x^4+4x^3+19x^2+9x-5?
- Math - potential zero - List all possible (or potential) rational zeros for the ...
- Pre Calc - 7x^3-24x^2-19x+12 -----------------=f(x) 2x^3-4x^2-40x+80 -Determine ...