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May 29, 2015

Homework Help: CHEM

Posted by leng on Saturday, September 22, 2012 at 2:36pm.

Aluminum reacts with Chlorine gas to form AlCl3. [2Al(s)+3Cl2(g)=2AlCl3(s)]
Given 11.0g of Al and 16.0g Cl2, if you had excess Al, how many moles of AlCl3 could be produced from 16.0g of Cl2?

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