Thursday

August 21, 2014

August 21, 2014

Posted by **Miaow** on Saturday, September 22, 2012 at 1:37pm.

8.) Caluclate the tension in the Atwood's Machine string for the case when m2 is 180 grams and m1 is 220 grams. Assume system is moving freely. The desired tension value is tension in string connected to 220 gram mass.

m1(g) -m2(g) = ma

.220(9.8) -.180(9.8) = .400a

2.156-1.764 = .400a

a=.98m/s^2

T - m1g = ma

T - .220(9.8) = .220(9.8)

T - 2.156 = .2156

T = 2.37

9.) Caluclate the tension in the Atwood's Machine string for the case when m2 is 180 grams and m1 is 220 grams. Assume system is moving freely. The desired tension value is tension in string connected to 180gram mass.

m1(g) -m2(g) = ma

.220(9.8) -.180(9.8) = .400a

2.156-1.764 = .400a

a=.98m/s^2

T - m2g = ma

T - .180(9.8) = .180(9.8)

T - 1.764 = .1764

T = 1.94

**Related Questions**

physics - Atwood's Machine An Atwood's machine consists of two masses, and , ...

English/Lit - I posted this earlier and someone suggested google-I did research...

college physics - When two objects of unequal mass are hung vertically over a ...

Algebra - I was wondering if someone could check over these answers for me. Find...

physics - A Modified Atwood's machine (the pulley with two mass system used in ...

Math - Can someone please check my answers below for accurateness? The ...

algebra - could someone check my answers to these few questions? "What is the ...

Physics - A simple Atwood's machine uses two masses, m1 and m2. Starting from ...

physics - A simple Atwood's machine uses two masses, m1 and m2. Starting from ...

Fractions / math - Okay, for these two questions I have the answers - but I can'...