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December 19, 2014

December 19, 2014

Posted by **fatima** on Saturday, September 22, 2012 at 11:43am.

- precalculus -
**bobpursley**, Saturday, September 22, 2012 at 12:33pmf(x)=i x, g(x)=i(x^2) where i is the sqrt(-1) for x>0

- precalculus -
**Steve**, Saturday, September 22, 2012 at 3:51pmwithout delving into complex numbers, maybe something like

f(x) = e^2x

g(x) = -e^-x

(fg)(x) = -e^x, which is decreasing

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