What is the amount of heat involved in each of the following?kilojoules to heat 240 of gold from 20 to 188
240 what? grams.
q = mass x specific heat x (Tfinal-Tinitial)
To calculate the amount of heat involved in heating gold from 20°C to 188°C, we need to use the formula:
Q = m * c * ΔT
where:
Q = amount of heat transferred (in joules)
m = mass of the substance (in kilograms)
c = specific heat capacity of the substance (in joules per kilogram per degree Celsius)
ΔT = change in temperature (in degrees Celsius)
First, let's convert the mass from grams to kilograms. Since the mass is given as 240 grams, we divide by 1000 to get 0.24 kilograms.
Next, we need to find the specific heat capacity of gold. The specific heat capacity of gold is approximately 0.13 joules per gram per degree Celsius.
Now we can substitute the values into the formula:
Q = 0.24 kg * 0.13 J/g°C * (188°C - 20°C)
First, we calculate the temperature difference:
ΔT = 188°C - 20°C = 168°C
Substituting the values:
Q = 0.24 kg * 0.13 J/g°C * 168°C
To simplify the units, we convert the specific heat capacity from joules per gram per degree Celsius to joules per kilogram per degree Celsius by dividing by 1000:
0.13 J/g°C = 0.13 J/1000 g°C = 0.00013 J/g°C
Substituting this value:
Q = 0.24 kg * 0.00013 J/g°C * 168°C
Finally, we can calculate the amount of heat:
Q = 0.24 kg * 0.00013 J/g°C * 168°C = 0.0063072 J
To convert this to kilojoules, we divide by 1000:
0.0063072 J / 1000 = 0.0063072 kJ
Therefore, the amount of heat involved in heating 240 grams of gold from 20°C to 188°C is approximately 0.0063072 kilojoules.