Posted by Travis on Friday, September 21, 2012 at 3:59pm.
(a) y = e^x, since y'' = y' = e^x (both positive)
(b) y = -e^-x, since
y' = e^-x positive
y'' = -e^-x negative
y = arctan(x) also fits here, since
y' = 1/(1+x^2) positive
y'' = -2x/(1+x^2)^2 negative
So the curve can change from concave up to concave down and still have decreasing slope
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