posted by Alyssa on .
When 47.5J of heat are added to 13.2 g of liquid, its temperature rises by 1.72 degrees C. What is the heat capacity of the liquid?
A cook wants to heat 1.35kg of water from 32.0 degrees C to 100 degrees C. If he uses combustion of natural gas to heat the water, hou much natural gas will he need to burn? Natural gas produces 49.3kJ of heat per gram. (for the sake of simplicity assume that the transger of heat is 100% efficient.)
q = mass liquid x sp. h. x (Tfinal-Tinitial)
Solve for sp.h.
How much heat is needed? That is
q = mass x specific heat x (Tfinal-Tinitial). Solve for q.
Then CH4 + 2O2 ==> CO2 + 2H2O
16 g CH4 x (q in Joules/49,300 J) = ? g CH4.