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December 19, 2014

December 19, 2014

Posted by **zohera** on Friday, September 21, 2012 at 12:50pm.

- math -
**Steve**, Friday, September 21, 2012 at 4:01pma^2b^(2/3) - (ab^2)^(2/3)

(a^2b)^(1/3) - (ab^2)^(1/3)(a^2b)^(1/3) + (ab^2)^(1/3)

ignoring the x's for a bit,

a^2 = (cot+tan)^2 = cot^2 + 2 + tan^2 = csc^2 + sec^2

a^2b = sec^3

b^2 = (sec-cos)^2 = sec^2 - 2 + cos^2

ab^2 = tan^3

(a2b)^(2/3) = sec^2

(ab^2)^(2/3) = tan^2

sec^2 - tan^2 = 1

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