Thursday

March 5, 2015

March 5, 2015

Posted by **Teniche** on Friday, September 21, 2012 at 4:50am.

- Stats -
**David Q/R**, Saturday, September 22, 2012 at 4:35pmX is exponentially distributed, so the probability density function f(x) = m.exp(-m.x), where E(X) = 1/m. You're told that the expected value is 10 mins, so 1/m = 10, so m = 1/10 = 0.1. So what you need to calculate is the integral of the pdf between 5 mins and 15 mins, that is, the integral of 0.1 times exp(-x/10) between those limits. That is -exp(-1.5) + exp(-0.5), which is approximately 0.383. So the probability of your having to wait between 5 and 15 minutes is 0.383. (I think I've got that right, but do check my reasoning.)

**Answer this Question**

**Related Questions**

stats - suppose that the wait time at the bank is uniformly distributed in the ...

Math - Bank XYZ is hiring, and they would like to determine the number of ...

math - A bank wishing to determine the average amount of time a customer must ...

Statistics - A hospital claims that the mean waiting time at its emergency room...

statistics - c. The arrival of large jobs at a computer centre forms a Poisson ...

Statistics - Assume the wait time to see a cardiologist at a certain clinic are ...

statistic - The amount of time a bank teller spends with each customer has a ...

AP Stats (math) - A large metropolitan area found that the time it takes for ...

Operation Management - Customers arrive at service window every 3.6 minutes(...

statistics - Waiting times at a doctor office are normally distributed with a ...