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December 21, 2014

December 21, 2014

Posted by **Anonymous** on Friday, September 21, 2012 at 4:03am.

- precal help -
**Scott**, Sunday, September 23, 2012 at 5:49pmn = d - 4

[(d - 4) / d] + [d / (d - 4)] = 5/2

multiplying by [2 * d * (d - 4)]

[2 (d - 4)^2] + (2 d^2) = 5 d (d - 4)

2d^2 - 16d + 32 + 2d^2 = 5d^2 - 20d

0 = d^2 - 4d - 32

factoring __ 0 = (d - 8)(d + 4)

0 = d - 8 __ 8 = d

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