Physics
posted by josephz on .
A group of engineering students constructs a slingshot to launch water balloons. The angle of launch is 30° and the initial velocity of the balloon is 14 m/s. The students launch a balloon from the roof of a building and the balloon lands 42 m away from the building. How tall is the building?

use the formula
y=xtanθ(g*X^2)/(2*v^2*Cos^2θ)
since it is on he roof,take y=y=H=height of the building
where x=42m
θ=30
V=14m/s
note: θ is not included in the exponent 2..just plugin the value..
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