Wednesday

October 1, 2014

October 1, 2014

Posted by **josephz** on Friday, September 21, 2012 at 12:27am.

(a) What was the initial velocity (magnitude and direction) of the rock?

(b) What was the magnitude of the velocity of the rock just before impact with the ground?

- Physics -
**drwls**, Friday, September 21, 2012 at 1:17am(a) They have already told you that the initial rock direction was vertical (up).

y = 500 + Vo*t - 16.1 t^2

= 0 then t = 6.5

0 = 500 + 6.5*Vo - 16.1*(6.5)^2

Solve for Vo.

V(t) = Vo - 16.1 t

Substitute t = 6.5 s and solve for V at that time.

The number 16.1 is the value of g/2, in units of ft/s^2

**Answer this Question**

**Related Questions**

Physics - A rock is thrown from on a cliff with the velocity of 15 m/s at an ...

Physics - A rock is thrown from on a cliff with the velocity of 15 m/s at an ...

Physics - 1.You are stuck on a cliff and want to know how far to the bottom. You...

physics - A rock is thrown vertically upward from the edge of a cliff. The rock ...

physics - A rock is thrown vertically upward from the edge of a cliff. The rock ...

Physics - Two rocks are thrown off the edge of a cliff that is 15.0 m above the ...

physics - c) A 0.26-kg rock is thrown vertically upward from the top of a cliff ...

physics - A 0.26 kg rock is thrown vertically upward from the top of a cliff ...

physics..help PLEASE! - A 0.26 kg rock is thrown vertically upward from the top ...

PHYSICS - A 0.26kg- rock is thrown vertically upward from the top of a cliff ...