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April 19, 2015

Posted by **josephz** on Friday, September 21, 2012 at 12:27am.

(a) What was the initial velocity (magnitude and direction) of the rock?

(b) What was the magnitude of the velocity of the rock just before impact with the ground?

- Physics -
**drwls**, Friday, September 21, 2012 at 1:17am(a) They have already told you that the initial rock direction was vertical (up).

y = 500 + Vo*t - 16.1 t^2

= 0 then t = 6.5

0 = 500 + 6.5*Vo - 16.1*(6.5)^2

Solve for Vo.

V(t) = Vo - 16.1 t

Substitute t = 6.5 s and solve for V at that time.

The number 16.1 is the value of g/2, in units of ft/s^2

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