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March 31, 2015

March 31, 2015

Posted by **michelle** on Thursday, September 20, 2012 at 10:49pm.

y = x^3/3 − x^2

- calculus -
**Steve**, Friday, September 21, 2012 at 10:09amwhat's the problem? A simple power rule exercise:

y = 1/3 x^3 - x^2

y' = 1/3 * 3 * x^(3-1) - 2*x^(2-1)

= x^2 - 2x

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