posted by nate on .
A tight-rope walker walks across a 30.0 m long wire tied between two poles. The center of the wire is displaced vertically downward by 1.0 m when he is half-way across. If the tension in both halves of the wire at this point is 3675 N, what is the mass of the tight-rope walker? Neglect the mass of the wire
the force diagram reflects the physical setup
the walker is 15.0 m from either end; and is displacing the wire 1.0 m
this means that the vertical component of the tension is one-fifteenth the tension in the wire (on BOTH sides)
so the force exerted by the walker is 3675/15 * 2
the mass of the walker is the force, divided by gravitational acceleration (g)