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February 28, 2015

February 28, 2015

Posted by **Shannon** on Thursday, September 20, 2012 at 8:19pm.

- Science (Physics) -
**bobpursley**, Thursday, September 20, 2012 at 8:31pma. avgvelocity=(final+starting)/2= 6m/s

acceleration=changevelocity/time=1/3 m/s^2

distance=distance first six seconds+distance for last 54 seconds

= avgvelocity*6+7*54=36m+378m

- Science (Physics) -
**xZ**, Wednesday, March 19, 2014 at 10:47pm456

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