A window washer drops a brush from a scaf-

fold on a tall office building.
What is the speed of the falling brush after
2.7 s? (Neglect drag forces.) The acceleration
due to gravity is 9.8 m/s2 .
Answer in units of m/s
How far has it fallen in that time?
answer in units of m

To find the speed of the falling brush after 2.7 seconds, we can use the equation of motion:

v = u + at

where:
v = final velocity (speed) of the brush
u = initial velocity of the brush (in this case, the brush was dropped and has an initial velocity of 0 m/s)
a = acceleration due to gravity (9.8 m/s^2)
t = time (2.7 seconds)

Plugging in the values, we have:

v = 0 + 9.8 * 2.7

v = 26.46 m/s

The speed of the falling brush after 2.7 seconds is approximately 26.46 m/s.

To calculate the distance the brush has fallen in that time, we can use the equation:

s = ut + 1/2 * a * t^2

where:
s = distance fallen
u = initial velocity of the brush (0 m/s)
a = acceleration due to gravity (9.8 m/s^2)
t = time (2.7 seconds)

Plugging in the values, we have:

s = 0 * 2.7 + 1/2 * 9.8 * (2.7)^2

s = 35.37 m

Therefore, the brush has fallen approximately 35.37 meters in 2.7 seconds.