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September 1, 2014

September 1, 2014

Posted by **Anonymous** on Thursday, September 20, 2012 at 5:34pm.

e^(4x+1)=p

log (kx)/ log (5) = c

- Math -
**Reiny**, Thursday, September 20, 2012 at 7:05pme^(4x+1)=p

ln(e^(4x+1)) = ln p

(4x+1) lne = lnp , but lne =1

4x+1 = lnp

4x = lnp - 1

x = (lnp - 1)/4

log (kx)/ log (5) = c

log( kx/log5) = c

kx/log5 = 10^c

kx = log5(10^c)

x = log5(10^c)/k

- correction - Math -
**Reiny**, Thursday, September 20, 2012 at 7:08pmscrap the solution to the second equation, I misread the question

here is the correct solution:

log (kx)/ log (5) = c

log kx = c log5

kx = 10^(c log5)

x = 10^(c log5) / k

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