Post a New Question

Math

posted by on .

Solve each equation for x

e^(4x+1)=p

log (kx)/ log (5) = c

  • Math - ,

    e^(4x+1)=p
    ln(e^(4x+1)) = ln p
    (4x+1) lne = lnp , but lne =1
    4x+1 = lnp
    4x = lnp - 1
    x = (lnp - 1)/4

    log (kx)/ log (5) = c
    log( kx/log5) = c
    kx/log5 = 10^c
    kx = log5(10^c)
    x = log5(10^c)/k

  • correction - Math - ,

    scrap the solution to the second equation, I misread the question
    here is the correct solution:

    log (kx)/ log (5) = c
    log kx = c log5
    kx = 10^(c log5)
    x = 10^(c log5) / k

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question