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December 19, 2014

December 19, 2014

Posted by **maura** on Thursday, September 20, 2012 at 3:39pm.

g(x)= x^2(1-2x)

g'(x)=

i tried doing

2x(1-2x)

2x-4x^2

- calculus -
**maura**, Thursday, September 20, 2012 at 3:45pmnever mind I got it but could someone just help me with this one.

A(s)= -11/s^6

- calculus -
**Steve**, Thursday, September 20, 2012 at 3:46pmA(s) = -11 * s^-6

so,

A' = 66*s^-7 = 66/s^7

- calculus -
**maura**, Thursday, September 20, 2012 at 3:58pmThank you!!

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