Posted by **Mayank** on Thursday, September 20, 2012 at 1:46pm.

A solid of density 5000 kg/m^3 weighs 0.5 kgf in air.It is completely immersed in water of density 1000 kg/m^3. Calculate the apparent weight of the solid in water.

- Physics -
**bobpursley**, Thursday, September 20, 2012 at 2:36pm
volume=.5kg/5000kg/m3= 100ml

mwass water displaced=100g

apparent mass=origianal-displaced=400g

- Physics -
**Sarthak**, Sunday, December 18, 2016 at 2:33am
We have,

Density of solid, d = 5000 kg/m3

Weight in air, W = 0.5 kgf = 0.5g N

Density of water, q = 1000 kg/m3

Let, V be the volume of the solid.

So, W = Vdg

=> 0.5g = V × 5000 × g

=> V = 10-4 m-3

So, Buoyant force is, B = Vqg = 10-4 × 1000 × g = 0.1 g N = 0.1 kgf

Thus, apparent weight = W – B = 0.5 – 0.1 = 0.4 kgf

## Answer This Question

## Related Questions

- PHYSCIS - a solid of density 5000 kgf weights 0.5 kgf in air . it is completely ...
- Physics - a solid of density 2700 kg/m³ and volume 0.0015 m³ is completely ...
- Singh - A solid weighs 1.5 kgf in air and 0.9 kgf in a liquid of density 1.2 ¡Á...
- physics - An object weighs 0.25N in air and 0.01N when immersed in water. ...
- physics - An object weighs 0.25N in air and 0.01N when immersed in water. ...
- physics - a 2.0 kg solid mass has an apparent weight 12.34N when totally ...
- physis - (1) A solid weight 0.04 Newton in air and 0.024 newton when fully ...
- physics - To verify her suspicion that a rock specimen is hollow,a geologist ...
- physics - A solid aluminum ingot weighs 88.0 N in air.What is its volume?The ...
- physics - To verify her suspicion that a rock specimen is hollow, a geologist ...

More Related Questions