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November 25, 2014

November 25, 2014

Posted by **edward** on Thursday, September 20, 2012 at 11:16am.

- mathematics -
**Steve**, Thursday, September 20, 2012 at 12:43pmwe know that a/sinA = b/sinB

if acosA = bcosB, then

a/cosB = b/cosA

b = acosA/cosB

b = asinB/sinA

so, acosA/cosB = asinB/sinA

cosAsinA = sinBcosB

sin2A = sin2B

means A=B and the triangle is isoceles

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