Posted by **Aa** on Thursday, September 20, 2012 at 8:28am.

From t = 0 to t = 3.30 min, a man stands still, and from t = 3.30 min to t = 6.60 min, he walks briskly in a straight line at a constant speed of 1.76 m/s. What are (a) his average velocity vavg and (b) his average acceleration aavg in the time interval 1.00 min to 4.30 min? What are (c) vavg and (d) aavg in the time interval 2.00 min to 5.30 min?

## Answer This Question

## Related Questions

- Physics - From t = 0 to t = 5.00 min, a man stands still, and from t = 5.00 min ...
- physical - From t = 0 to t = 3.30 min, a man stands still, and from t = 3.30 min...
- physics - From t = 0 to t = 3 min 25 seconds, a man stands still, and from t = 3...
- math - 289 min = 4 hr and 49 min 213 min = 3 hr and 33 min 345 min = 5 hr and 45...
- Physics - Could someone please review my answers and tell me if I am on the ...
- chemistry - A particular radioactive substance has a half-life of 4 minutes. How...
- MATH!! - TO be on the 1-km race team, Celia must have a mean time less than 5 ...
- Math - Please help me solve these problem i have no idea how to do this. 720m/d...
- physics - A person travels by car from one city to another with different ...
- Chemistry(Please check) - The units of a rate constant for zero, first, and ...

More Related Questions