posted by Aa on .
From t = 0 to t = 3.30 min, a man stands still, and from t = 3.30 min to t = 6.60 min, he walks briskly in a straight line at a constant speed of 1.76 m/s. What are (a) his average velocity vavg and (b) his average acceleration aavg in the time interval 1.00 min to 4.30 min? What are (c) vavg and (d) aavg in the time interval 2.00 min to 5.30 min?
do you have a question about this?
avgvelociyt=total distance/total time
avg acceleratio=changevelociyt/total time