Posted by **fernando** on Wednesday, September 19, 2012 at 11:17pm.

find the constants a and b so that the function is continuous on the entire real line. F(x)= 3, x≤-1

ax+b, -1<x<2

-3,x≥2 Help???

- calculus -
**Steve**, Thursday, September 20, 2012 at 11:03am
A little more legibly,

f(x)

= 3 for x<=1

= ax+b for 1<x<2

= -3 for x>=2

So, you need to find a line connecting (-1,3) with (2,-3) so there are no holes in the graph.

That's just a simple two-point line problem:

(y-3)/(x+1) = -6/3 = -2

y-3 = -2(x+1)

y = -2x + 1

So, f(x) = -2x+1 for -1<x<2

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