An apple falls from a tree and hits the ground

9.93 m below.
With what speed will it hit the ground?
The acceleration of gravity is 9.8 m/s2 .
Answer in units of m/s

1.013265306

32 To determine the speed at which the apple hits the ground, we can use the equations of motion.

The general equation to calculate the final velocity (v) is given by:

v^2 = u^2 + 2as

Where:
v = final velocity (what we want to find)
u = initial velocity (assuming the apple starts from rest, the initial velocity is 0)
a = acceleration due to gravity (9.8 m/s^2)
s = distance fallen (9.93 m)

Substituting the given values into the equation:

v^2 = 0^2 + 2 * 9.8 * 9.93

Simplifying:

v^2 = 0 + 196.04

v^2 = 196.04

To find v, we take the square root of both sides:

v = √196.04

v ≈ 14 m/s

Therefore, the apple will hit the ground with an approximate speed of 14 m/s.