how many silver coins weighing 26g each would take to provide 5 moles of silver
number=5molesAg*XXXXgrams/mole * 1/26 grams)
To determine the number of silver coins needed to provide 5 moles of silver, we need to calculate the total mass of 5 moles of silver and then divide it by the mass of each silver coin.
Step 1: Determine the molar mass of silver.
The molar mass of silver (Ag) is approximately 107.87 g/mol. This means that 1 mole of silver weighs 107.87 grams.
Step 2: Calculate the mass of 5 moles of silver.
To find the mass of 5 moles of silver, multiply the molar mass by the number of moles:
5 moles x 107.87 g/mol = 539.35 grams.
Step 3: Divide the total mass by the mass of each silver coin.
Since each silver coin weighs 26 grams, divide the total mass by 26 grams:
539.35 grams / 26 grams = 20.75.
So, it would take approximately 20.75 (rounded to the nearest whole number) silver coins weighing 26 grams each to provide 5 moles of silver. Since we cannot have a fraction of a coin, you would need at least 21 silver coins to provide 5 moles of silver.