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March 29, 2017

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Sulfuric acid (H2SO4) is prepared commercially from elemental sulfur using the contact process. In a typical sequence of reactions, the sulfur is first burned:
S + O2 → SO2 ,
then it is converted to SO3 using a catalyst:
2 SO2 + O2 → 2 SO3 .
The resulting SO3 is reacted with water to produce the desired product:
SO3 + H2O → H2SO4 .
How much sulfuric acid could be prepared
from 34 moles of sulfur?
Answer in units of g

  • AP Chemistry - ,

    This is a regular stoichiometry problem. You can work it as three problems OR you can collapse the three into one problem with a shortcut.
    Method 1: Three problems.
    S + O2 ==> SO2. 34 mol S; calculate mols SO2 formed. Then
    2SO2 + O2 ==> 2SO3. Use mols SO2 from the first problem and calculate mols SO3 formed.
    SO3 + H2O ==> H2SO4. Use mols SO3 from second problem and calculate mols H2SO4 formed.

    Method 2:
    Write all of the equations.
    S + O2 --> SO2
    2SO2 + O2 ==> 2SO3
    SO3 + H2SO4 = H2SO4.
    Now watch this. Using the coefficients in the balanced equation we have
    1 mol S = 1 mol SO2
    2 mol SO2 = 2 mol SO3 or 1-->1
    1 mol SO3 = 1 mol H2SO4
    Therefore we can see that 1 mol S forms 1 mol H2SO4 and it seems obvious then that 34 mols S will produce 34 mols H2SO4.

  • AP Chemistry - ,

    So that would also equal 34 grams right?

  • AP Chemistry - ,

    No. The problem asked for mols and answer is 34 mols S. A mol of S has a mass of 32.066 grams; therefore, 34 mols will be 34 x 32.066 = a bunch of grams.

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