Post a New Question


posted by .

To move a large crate across a rough floor, you push on it with a force F at an angle of 21¨¬ below the horizontal. The mass of the crate is 31 kg, ¥ìs is 0.57, and ¥ìk is 0.45. Find the force necessary to start the crate moving

  • phsyics -

    x: Fcosα –F(fr) =0
    y: N-mg-Fsinα = 0 =>
    N= mg+Fsinα
    Fcosα =F(fr) =μ⒦•N = μ⒦• (mg+Fsinα)
    F= μ⒦•m•g/ (cosα - μ⒦•sinα) =
    =0.45•31•9.8/(cos40-0.45•sin40) = 286.7 N
    (this is the force that necessary to move)
    F= μ⒮•m•g/ (cosα - μ⒮•sinα) =
    =0.57•31•9.8/(cos40-0.57•sin40) = 433.3 N
    (this is the force that necessary to start the motion)

Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions

Post a New Question