Posted by **Jun** on Wednesday, September 19, 2012 at 7:22am.

in a quadrilateral ABCD, BC is parallel to AD. AB = BC, 13CD = 20BC and 34AB = 13AD. H is a point on AD such that CH is perpendicular to AD. Prove that 5CH = 3CD

## Answer This Question

## Related Questions

- geometry - A quadrilateral has vertices A(3, 5), B(2, 0), C(7, 0), and D(8, 5). ...
- maths - Given is a quadrilateral ABCD,diagonals AC and BDare such that AO=BO=CO=...
- algbra - a parallelogram is a quadrilateral whose opposite sides are parallel. ...
- maths - ABCD is a convex cyclic quadrilateral such that AB=AD and ∠BAD=90...
- maths - ABCD is a convex cyclic quadrilateral such that AB=AD and ∠BAD=90...
- math - in a Quadrilateral ABCD, AB=AD and CB=CD. Prove that- (1) AC bisects ...
- plllllllllls help math - ABCD is a convex quadrilateral with AC and BD ...
- Geometry - quadrilateral A B C D on a graph. Point A is at ( -5, -1), Point B ...
- math - The vertices of quadrilateral ABCD are (A(1,1), B(1,5), C(5,5) and D(7,1...
- Geometry - The coordinates of the vertices of quadrilateral ABCD are A (-8, 8...

More Related Questions