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November 27, 2014

November 27, 2014

Posted by **Rebekah** on Wednesday, September 19, 2012 at 6:53am.

thanks

- pre calc -
**Damon**, Wednesday, September 19, 2012 at 7:48amI can not read your radius so call it R.

I assume the point of the one is down.

the radius of the water surface at height h is r = (16/R)h

the area of that water surface is pi r^2

The volume of a horizontal slice dh is

pi r^2 dh

which is

pi (16/R)^2 h^2 dh

so integrating the volume at height h is

V(h) = pi (16/R)^2 h^3 /3

if for example R were 4 feet then

V(h) = pi (16/3) h^3

- pre calc -
**Steve**, Wednesday, September 19, 2012 at 11:10amor, just using similar cones, at height h, the surface of the water has a radius which can be found by

R/16 = r/h

r = hR/16

v = 1/3 pi r^2 * h

= pi/3 (hR/16)^2 * h

= pi/3 * R^2/256 * h

Hmmm. Better check both our maths - we disagree.

- pre calc -
**Reiny**, Wednesday, September 19, 2012 at 11:45amor , assuming you are saying the radius of the cone is 4 ft,

let the height of water be h

and the radius of the water level be r

r/h = 4/16 = 1/4

r = h/4

V = (1/3)πr^2 h

= (1/3)π(h^2/16)h

= (π/48)h^3

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