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A glucose solution contains 55.0g of glucose C6H12O6 in 475g of water.
Compute the freezing point and boiling point of the solution. Assume a density of 1.00g/mL for water.

  • Chemistry - ,

    mols glucose = grams/molar mass. Solve for mols.
    m = mols/Kg solvent
    m = mols/0.475 = ?

    Substitute m into
    delta T = Kf*m and subtract from 0 C for the new freezing point

    and delta T = Kb*m and add to 100 for the new boiling point.
    Kf = 1.86 and Kb = 0.51

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