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December 22, 2014

December 22, 2014

Posted by **ben** on Tuesday, September 18, 2012 at 10:15pm.

f(x) = Ax^2 + Bx + C

where A; B and C are real numbers and A = 0; they are (1/2,0);(0,10); and (4,0). Find a quadratic

function that satisfy es these three points.

- Math -
**Count Iblis**, Tuesday, September 18, 2012 at 10:42pmForm the igven points, you see that at x = 1/2 and at x = 4 the function is zero. This means that the function is proportional to:

(x - 1/2) (x - 4)

So, we can put:

f(x) = D (x - 1/2) (x - 4)

To find D, you use that at f(0) = 10:

f(0) = 2 D = 10 ----->

D = 5

Therefore:

f(x) = 5 (x - 1/2) (x - 4) =

5 x^2 - 45/2 x + 10

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