The total ticket sales for the school basketball game were $1625. Adult tickets were $7 and the student tickets were $3. Twice as many students bought tickets as adults. How many adult and student tickets were sold?

125

The laurelwood pta is presenting it's 5th annual talent show and Kate is collected tickets at the door. The gym is filled with 215 students and adults students tickets are .50 and adults tickets are 2.00. If Kate collected 250.00 how many adults and how many students purchased tickets?

Let's suppose the number of adult tickets sold is "x".

The number of student tickets sold is twice the number of adult tickets, so it will be 2x.

The total amount earned from adult tickets would be 7 * x = 7x.

The total amount earned from student tickets would be 3 * 2x = 6x.

Adding both amounts gives us the total ticket sales: 7x + 6x = 1625.

Combining like terms: 13x = 1625.

To find x, divide both sides of the equation by 13: x = 1625 / 13.

Thus, x ≈ 125.

So, the number of adult tickets sold is 125.

The number of student tickets sold is 2 * 125 = 250.

To solve this problem, we can set up a system of equations. Let's start by defining our variables:

Let x be the number of adult tickets sold.
Let y be the number of student tickets sold.

From the information given, we can set up the following equations:
Equation 1: 7x + 3y = 1625 (equation for the total ticket sales, with adult tickets at $7 each and student tickets at $3 each)
Equation 2: y = 2x (since twice as many students bought tickets as adults)

Now we can solve the system of equations.

Substitute Equation 2 into Equation 1:
7x + 3(2x) = 1625
7x + 6x = 1625
13x = 1625
Divide both sides by 13:
x = 125

Now we can substitute the value of x back into Equation 2 to find y:
y = 2(125)
y = 250

Therefore, 125 adult tickets and 250 student tickets were sold.