Posted by Taylor on Tuesday, September 18, 2012 at 7:06pm.
Plug the values you have into the formula y = y[initial] + 1/2gt^2
Remember 1/2g is a negative value!
y[initial] is going to be the height the bullet starts from, or rather the height at which the gun is held. g is the standard gravitational acceleration. Y will just be zero, since the final height of the bullet will be the ground, or 0.
Next, solve! Subtract y[initial] from y, and then divide by 1/2g. This will equal t^2. Take the square root and viola!
For the second part of the question, use the distance formula: d = vt + 1/2at^2.
Once again, a will be the gravitational acceleration, and negative!
Not sure about the last one....
Hope it helps!
This is wrong!
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