Posted by Rosmery on Tuesday, September 18, 2012 at 4:25pm.
Prob(2) = 1/36
prob(3) = 2/36
prob(4) = 3/36
prob(12) = 1/36
prob(11) = 2/36
prob(10) = 3/36
total of above , your cases of winning = 12/36
so the prob of remaining cases = 24/36
expected value of game
= (12/36)(5) + (24/36)(-5)
= (1/3)(5) - (2/3)(5
= -5/3
You would be expected to lose $1.67
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