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September 20, 2014

September 20, 2014

Posted by **katie** on Tuesday, September 18, 2012 at 3:16pm.

(y-(10/y))^2+6(y-(10/y))-27=0

- precal -
**Steve**, Tuesday, September 18, 2012 at 3:45pm(y-(10/y))^2+6(y-(10/y))-27=0

his is just like the other one: Let u=y-1/y and you have

u^2 + 6u -27 = 0

(u+9)(u-3) = 0

(y - 10/y + 9)(y - 10/y - 3) = 0

(y^2 + 9y - 10)(y^2 - 3y - 10) = 0

(y+10)(y-1)(y-5)(y+3) = 0

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