Posted by **Donald** on Tuesday, September 18, 2012 at 2:12pm.

In reahcing her destination, a backpacker walks with an average velocity of 1.29 m/s, due west. This average velocity results because she hikes for 6.44 km with an average velocity of 2.59 m/s, due west, turns around, and hikes with an average velocity of 0.44 m/s, due east. How far east did she walk?

- Physics -
**Steve**, Tuesday, September 18, 2012 at 3:25pm
net distance divided by total time is 1.29m/s

Since time = distance/speed,

(6400-d)/(6400/2.59 + d/.44) = 1.29

d = 817m or .817km

check: she walked west for 6440/2.59 = 2486 s

she walked east for 817/.44 = 1857s

net distance from start: 5623m

total time hiking: 2486+1857 = 4343s

5623m/4343s = 1.29m/s

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