Posted by Anonymous on Monday, September 17, 2012 at 4:31pm.
A projectile is fired from the top of a cliff at 14.2 m/s at an angle of 36.9 degrees below the horizontal, and strikes water at the same level as the base of the cliff 3.51 seconds later. (Assume g=10.0 m/s2.)
How high was the top of the cliff above the water?

Physics 124  Steve, Monday, September 17, 2012 at 5:14pm
all we care about is the downward velocity. Initially that is
14.2 cos 36.9° = 11.36 m/s
so, starting from height H, the height after t seconds is
11.36t  4.9 t^2
at t=3.51,
h = 100.24 m
So, the cliff is 100.24m high
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