Posted by Alex on Monday, September 17, 2012 at 3:53pm.
y <= x+200
x+2y <= 1600
maximize 14x+22y-900
Surely (0,0) will not yield maximum profit!
If you evaluate p(x,y) at the line intersections, you will find
p(0,0) = -900
p(0,200) = 3500
p(400,600) = 17900
p(1600,0) = 21500
x = 14,y = -2
x = 14,y = -2
x = 14,y = -2
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