Monday

July 14, 2014

July 14, 2014

Posted by **Alex** on Monday, September 17, 2012 at 3:53pm.

I think it's b but I'm not really sure. Can someone show me how to do this or let me check my answer? :)

14x + 22y – 900. The production of y can exceed x by no more than 200 units. Moreover, production levels are limited by the formula x + 2y ≤ 1600. What production levels yield maximum profit?

a. x = 400; y = 600

b. x = 0; y = 0

c. x = 1,600; y = 0

d. x = 0; y = 200

- math -
**Steve**, Monday, September 17, 2012 at 4:04pmy <= x+200

x+2y <= 1600

maximize 14x+22y-900

Surely (0,0) will not yield maximum profit!

If you evaluate p(x,y) at the line intersections, you will find

p(0,0) = -900

p(0,200) = 3500

p(400,600) = 17900

p(1600,0) = 21500

- math -
**abdul**, Monday, October 1, 2012 at 4:08pmx = 14,y = -2

- math -
**abdul**, Monday, October 1, 2012 at 4:12pmx = 14,y = -2

- x = 14,y = -2 -
**abdul**, Monday, October 1, 2012 at 4:13pmx = 14,y = -2

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