posted by David on .
A person walks the path shown below. The total trip consists of four straight-line paths.
Path 1 is 40.0 m due east.
Path 2 is 170.0 m due south.
Path 3 is 120.0 m 30.0° south of west.
Path 4 is 190.0 m 60.0° north of west.
At the end of the walk, what is the person's resultant displacement?
( meters and degrees south of west)
40E = (40,0)
170S = (0,-170)
120W30°S = (-103.9,-60)
190W60°N = (-95,165.5)
Add them up to get (31.1,-64.5) = 71.6m W64°S