Posted by **David** on Monday, September 17, 2012 at 3:49pm.

A person walks the path shown below. The total trip consists of four straight-line paths.

Path 1 is 40.0 m due east.

Path 2 is 170.0 m due south.

Path 3 is 120.0 m 30.0° south of west.

Path 4 is 190.0 m 60.0° north of west.

At the end of the walk, what is the person's resultant displacement?

( meters and degrees south of west)

- Physics -
**Steve**, Monday, September 17, 2012 at 5:42pm
40E = (40,0)

170S = (0,-170)

120W30°S = (-103.9,-60)

190W60°N = (-95,165.5)

Add them up to get (31.1,-64.5) = 71.6m W64°S

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