Suppose a moose jumps straight up with an initial upward velocity of 95 m/s. How long until the ungulate lands back on the ground, where it belongs?
Tr = (V-Vo)/g = (0-95)/-9.8 = 9.69 s. =
Rise time or time to reach max ht.
Tf = Tr = 9.69 s. = Fall time.
Tr + Tf = 9.69 + 9.69 = 19.4 s. = Time
for moose to land back on the gnd where
it belongs.