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January 31, 2015

January 31, 2015

Posted by **Becky** on Monday, September 17, 2012 at 11:30am.

lim (x, y)→(0, 0) [(3e^−x^2− y^2) − 3]/

(x^2 + y^2)

- calc 3 -
**Steve**, Monday, September 17, 2012 at 11:39amin polar coordinates, we have

lim (r->0) (3e^-(r^2)-3)/r^2

= lim -6re^(-r^2))/2r

= lim -6e^(-r^2)/2

as r-> 0, lim = -3

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