# Math

posted by
**Johnathan**
.

Prove that:

P(A n B^c) = P(A U B) - P(B)

and

P(A n B^c) = P(A) - P(A n B)

posted by
**Johnathan**
.

Prove that:

P(A n B^c) = P(A U B) - P(B)

and

P(A n B^c) = P(A) - P(A n B)