posted by Jake .
find an equation of the line tangent to the equation at the given point.
f(x)=5x^2 at x=10
when x=10 , f(10)=500
so your point is (10,500)
f'(x) = 10x
then when x=10 , slop = 100
Now you have a slope of 100 and a point of (10,500)
Use the method you learned to find the equation of the tangent (a straight line)