Posted by **Jake** on Sunday, September 16, 2012 at 11:42pm.

find an equation of the line tangent to the equation at the given point.

f(x)=5x^2 at x=10

- Calculus -
**Reiny**, Monday, September 17, 2012 at 8:00am
when x=10 , f(10)=500

so your point is (10,500)

f'(x) = 10x

then when x=10 , slop = 100

Now you have a slope of 100 and a point of (10,500)

Use the method you learned to find the equation of the tangent (a straight line)

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