Posted by **cheri** on Sunday, September 16, 2012 at 10:59pm.

A sample of air contains 38.5 ìg/m3 of beryl-

lium dust. How many atoms of beryllium are

present in a room with dimensions of 8 feet by

12.9 feet by 17.1 feet?

Answer in units of atoms

- ap -
**DrBob222**, Sunday, September 16, 2012 at 11:07pm
What unit is ig/m3?

- ap -
**cheri**, Sunday, September 16, 2012 at 11:24pm
i think its suppose to be the u symbol thing.

- ap -
**DrBob222**, Sunday, September 16, 2012 at 11:30pm
OK We'll assume 38.5 ug/m^3.

I would convert 8 feet,12.9 feet, and 17.1 feet to meters.

Then volume of room is length x width x height in m^3.

Total Be is 38.5 ug/m^3 x volume room = ug Be. That x 1E-6 converts ug Be to grams Be. Convert to mols (mol = grams/molar mass) and that x 6.02E23 = atoms Be.

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