ap
posted by cheri on .
A sample of air contains 38.5 ìg/m3 of beryl
lium dust. How many atoms of beryllium are
present in a room with dimensions of 8 feet by
12.9 feet by 17.1 feet?
Answer in units of atoms

What unit is ig/m3?

i think its suppose to be the u symbol thing.

OK We'll assume 38.5 ug/m^3.
I would convert 8 feet,12.9 feet, and 17.1 feet to meters.
Then volume of room is length x width x height in m^3.
Total Be is 38.5 ug/m^3 x volume room = ug Be. That x 1E6 converts ug Be to grams Be. Convert to mols (mol = grams/molar mass) and that x 6.02E23 = atoms Be.